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Posts by Peter Taylor
I've read one novel with a similar setting where the answer was: a small number in the government know the truth, but they intentionally deceive everyone else in order to retain power. Anyone who w...
Simple strategy A greedy strategy works. Place X in squares 1, 2. (1, 2) excludes 3. Available: (4, 5, 6, 7, 8, 9, 10, 11, 12, 13). Place X in square 4. (1, 4) excludes 7. (2, 4) excludes 6....
My solution ExplanationThis works by using the Roman numeral V for five. There are ten "simple" Vs formed by each half-line and its clockwise neighbour, and I would argue also for ten additional...
Reasoning and solutionThere must be at least 7 1-dollar bills, at least 8 2-dollar bills, and at least 11 5-dollar bills. That constrains 26 of the 26 bills, so the total is 7 + 16 + 55 = 78 dollar...
+---+---+---+---+ | | | 0 0 1 3 | + + | | | 1 1 0 3 | + + | | | 2 3 3 2 | + + | ...
Proposed solution123121321 for 9 symbols. Reasoning The first three symbols should be a permutation because otherwise we can trim the first symbol without losing any permutation. Without loss of ...
A solution using fewer than 6 of the numbers $$\left(75 + \frac{50}{25}\right)\times 7 + 100 = 639$$
Solution- Reasoning Two of the same sign collapse to +; two different signs collapse to -. This is isomorphic to the multiplication rules, so the entire question is isomorphic to: A large whit...
Solution 27 34 41 48 19 31 43 55 11 28 45 62 3 25 47 69 Reasoning Filling in the first column as an arithmetic progression and then the rows as arithmetic progressions we get...
If we supposeA+B=2, A+C=4, B+C=8 thenGaussian elimination gives A=-1, B=3, C=5. The only restriction(other than the obvious observation that the sums must also be distinct) is that the sums must a...
If both the CA and the client software follow the RFC, the client software will refuse the cert. Section 4.2 (Certificate Extensions) of the RFC you link states ... Each extension in a certific...
Solution Process An easy observation is that every triangle has an edge which the line does not pass through, so we're really tiling with four diamonds: I placed the red diamond arbitraril...
Solution Process I start with a fairly symmetric placement which doesn't meet the constraints and make simple modifications until it does. We have two "single" and two "double" tiles per sid...
Answer4 amazons. Achieving the claimed result .A... ....A ..... A.... ...A. The claimed result is optimal If we have five amazons then every rank and file must have one. Consider the c...
Solution Yes, by Sprague-Grundy. The same comment as I made on the related question applies. Answer to what I suppose to be the intended question $146$ is an N-position (the next player to mov...
