Welcome to the staging ground for new communities! Each proposal has a description in the "Descriptions" category and a body of questions and answers in "Incubator Q&A". You can ask questions (and get answers, we hope!) right away, and start new proposals.
Are you here to participate in a specific proposal? Click on the proposal tag (with the dark outline) to see only posts about that proposal and not all of the others that are in progress. Tags are at the bottom of each post.
Post History
If we supposeA+B=2, A+C=4, B+C=8 thenGaussian elimination gives A=-1, B=3, C=5. The only restriction(other than the obvious observation that the sums must also be distinct) is that the sums must a...
#2: Post edited
by
Peter Taylor
·
2026-06-22T10:20:23Z (3 months ago)
<details><summary>If we suppose</summary>A+B=2, A+C=4, B+C=8</details> <details><summary>then</summary>Gaussian elimination gives A=-1, B=3, C=5.</details>
- <details><summary>If we suppose</summary>A+B=2, A+C=4, B+C=8</details> <details><summary>then</summary>Gaussian elimination gives A=-1, B=3, C=5.</details>
- <details><summary>The only restriction</summary>(other than the obvious observation that the sums must also be distinct) is that the sums must all be even. Perhaps the intention was that people would assume that any solution can be divided down to a case when the smallest sum is 1 and would then conclude that it is unsolvable?</details>
#1: Initial revision
by
Peter Taylor
·
2026-06-22T10:17:37Z (3 months ago)
<details><summary>If we suppose</summary>A+B=2, A+C=4, B+C=8</details> <details><summary>then</summary>Gaussian elimination gives A=-1, B=3, C=5.</details>