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Incubator Q&A Rearrange to make 5 fives

My solution ExplanationThis works by using the Roman numeral V for five. There are ten "simple" Vs formed by each half-line and its clockwise neighbour, and I would argue also for ten additional...

posted 29d ago by Peter Taylor‭

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#1: Initial revision by

Peter Taylor‭ · 2026-08-19T08:06:29Z (29 days ago)

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<details><summary>My solution</summary>

![All five lines positioned so that their centres are on top of each other and rotated by different multiples of 72 degrees](https://proposals.codidact.com/uploads/s2mfjd7x05tpeo4wxfbc9j0yl69s)</details>
<details><summary>Explanation</summary>This works by using the Roman numeral V for five. There are ten "simple" Vs formed by each half-line and its clockwise neighbour, and I would argue also for ten additional Vs formed by each half-line and its next-but-one clockwise neighbour.
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