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Subdividing a circle into 2 halves with equal number of letters A, B and C in each half Question
Draw a straight line through the center of the circle below to subdivide it into two halves so that each half will have the same number of occurrences of the letter A. Also each half will have the same number of B's and the same number of C's.
1 answer
The following users marked this post as Works for me:
| User | Comment | Date |
|---|---|---|
| will.octagon.gibson | (no comment) | Apr 10, 2026 at 15:51 |
Answer
Solution method
First count how many As, Bs, and Cs there are, which is 6 each. That means we are looking for a break that leaves 3 on each side.There are a total of 18 letters, so 9 different dividing lines that leave whole letters on both sides. That's a small enough solution space to simply search exhaustively.
Surprisingly, that worked. I was expecting it not to work and a "clever" interpretation of the problem statement would be required such that the line would include parts of two letters on either side.
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